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18.9 mL of 1.5M solution A and 27.8 mL of 2.5M solution B are mixed together.

What is the new concentration of substance B after they are mixed?

Enter your answer as a number without a unit.

Answer :

Final answer:

The new concentration of substance B in a mixed solution of A and B can be found by calculating the amount of substance B in moles in the initial solution, and then recalculating the molarity after the solutions are mixed. The final molarity of substance B is found to be approximately 1.49M.

Explanation:

This question can be solved using the concept of molarity and dilution in chemistry. Molarity is defined as the number of moles of a solute per litre of a solution.

Firstly, find the amount of substance B in moles it's in solution B using the formula mol = Molarity * volume. In this case, mol of B = 2.5M * 27.8mL = 69.5mmol. Remember to convert mL to L when performing the multiplication.

After mixing solution A and B, the total volume is 18.9mL + 27.8mL = 46.7mL. To find the new concentration of B, use the formula Molarity = moles/volume. Therefore, the new concentration of B = 69.5mmol / 46.7 mL = 1.49M approximately.

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Final answer:

The new concentration of substance B after mixing is 97.85.

Explanation:

The concentration of substance B after mixing:

To find the new concentration of substance B after mixing, we can use the equation:

(volume of solution A x concentration of solution A) + (volume of solution B x concentration of solution B)

Substituting the given values into the equation:

(18.9 mL x 1.5) + (27.8 mL x 2.5) = 28.35 + 69.5 = 97.85

Therefore, the new concentration of substance B after mixing is 97.85.

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