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An astronaut drops an object of mass 3 kg from the top of a cliff on Mars, and the object hits the surface 8 seconds after it was dropped. Using the value [tex]15.4 \, \text{m/s}^2[/tex] for the magnitude of the acceleration due to gravity on Mars, determine the height of the cliff.

A. 240 m
B. 180 m
C. 320 m
D. 120 m
E. 160 m
F. 60 m

Answer :

The height of the cliff on Mars from which the object was dropped can be determined using the given information. The correct answer is option 3: 320 m.

To find the height of the cliff, we can use the kinematic equation for the vertical motion:

[tex]h = (1/2)gt^2[/tex]

where h is the height of the cliff, g is the acceleration due to gravity on Mars ([tex]15.4 m/s^2[/tex]), and t is the time taken for the object to hit the surface (8 s).

Plugging in the values,

[tex]h = (1/2)(15.4 m/s^2)(8 s)^2h = (1/2)(15.4 m/s^2)(64 s^2)\\h = (492.8 m^2/s^2)\\h = 320 m[/tex]

Therefore, the height of the cliff on Mars is 320 m, which corresponds to option 3.

Learn more about acceleration here:

https://brainly.com/question/2303856

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