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Answer :
To determine the approximate power output of the reactor, we will follow these steps:
Calculate the Energy Produced per Fission:
Each fission of a uranium-235 ([tex]^{235}_{92}U[/tex]) nucleus releases 185 MeV of energy.
Convert this energy to joules (J). Note that 1 eV = $1.602 \times 10^{-19}$ J, so:
[tex]185 \text{ MeV} = 185 \times 10^6 \text{ eV} \times 1.602 \times 10^{-19} \text{ J/eV}[/tex]
[tex]185 \text{ MeV} = 2.9637 \times 10^{-11} \text{ J}[/tex]
Determine the Number of Fissions in 2 kg of [tex]^{235}_{92}U[/tex]:
The molar mass of uranium-235 is approximately 235 g/mol.
Calculate the number of moles in 2 kg:
[tex]\text{Number of moles} = \frac{2000 \text{ g}}{235 \text{ g/mol}} \approx 8.51 \text{ mol}[/tex]
Use Avogadro's number ($6.022 \times 10^{23}$ atoms/mol) to calculate the total number of atoms in 2 kg:
[tex]\text{Number of atoms} = 8.51 \text{ mol} \times 6.022 \times 10^{23} \text{ atoms/mol}[/tex]
[tex]\approx 5.12 \times 10^{24} \text{ atoms}[/tex]
Calculate the Total Energy Produced:
Multiply the number of fissions by the energy per fission:
[tex]\text{Total energy} = 5.12 \times 10^{24} \times 2.9637 \times 10^{-11} \text{ J}[/tex]
[tex]\approx 1.517 \times 10^{14} \text{ J}[/tex]
Find the Power Output:
Power is the rate of energy consumption over time.
Convert 30 days to seconds (since 1 day = 24 hours, 1 hour = 3600 seconds):
[tex]30 \text{ days} = 30 \times 24 \times 3600 \text{ seconds} = 2.592 \times 10^6 \text{ seconds}[/tex]
Use the power formula, [tex]P = \frac{E}{t}[/tex]:
[tex]P = \frac{1.517 \times 10^{14} \text{ J}}{2.592 \times 10^6 \text{ seconds}}[/tex]
[tex]\approx 5.85 \times 10^7 \text{ W}[/tex]
Therefore, the approximate power output of the [tex]^{235}_{92}U[/tex] reactor is 58.5 MW (megawatts).
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