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Answer :
Final answer:
The change in velocity of the bowling ball is 10.2 m/s, calculated using the impulse-momentum principle, where the impulse equals the product of the force and the time interval for which the force acts.
Explanation:
The change in velocity of the bowling ball can be calculated using the principle of impulse and momentum. The impulse experienced by an object is equal to the change in momentum of the object. Impulse is given by the product of the force acting on the object and the time for which it acts.
To find the change in velocity (Δv), we use the equation:
Impulse (J) = Force (F) × Time (t) = Change in Momentum (mΔv)
Substitute the given values into the equation:
J = 186 N × 0.40 s
J = 74.4 kg·m/s
Now, applying the same impulse to the change in momentum:
74.4 kg·m/s = 7.3 kg × Δv
We solve for Δv:
Δv = 74.4 kg·m/s / 7.3 kg
Δv = 10.2 m/s
Therefore, the change in velocity of the bowling ball is 10.2 m/s.
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