We appreciate your visit to Find three consecutive integers such that the sum of the second and triple the third is 193 more than the first. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
Final answer:
To solve the problem, one can form an algebraic equation based on the provided conditions and solve for 'n'. The three consecutive integers for this problem are 94, 95, and 96.
Explanation:
This question is a type of algebraic word problem that involves consecutive integers. In this case, we need to find three consecutive integers so that the sum of the second integer and triple the third integer equals a value that is 193 more than the first integer.
To solve this, let's define the first integer as 'n'. Since the integers are consecutive, the second and third ones can be defined as 'n+1' and 'n+2', respectively.
According to the problem, the sum of the second integer and three times the third integer is 193 more than the first. This forms our equation: (n+1) + 3(n+2) = n + 193.
Solving the equation gives us n = 94. Therefore, the three consecutive integers are 94, 95, and 96.
Learn more about Consecutive Integers here:
https://brainly.com/question/35707212
#SPJ11
Thanks for taking the time to read Find three consecutive integers such that the sum of the second and triple the third is 193 more than the first. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
- Why do Businesses Exist Why does Starbucks Exist What Service does Starbucks Provide Really what is their product.
- The pattern of numbers below is an arithmetic sequence tex 14 24 34 44 54 ldots tex Which statement describes the recursive function used to..
- Morgan felt the need to streamline Edison Electric What changes did Morgan make.
Rewritten by : Barada
