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A 25.0 mL sample of a saturated Ca(OH)2 solution is titrated with 0.028 M HCl, and the equivalence point is reached after 38.1 mL of titrant are dispensed. Based on this data, what is the concentration (M) of the hydroxide ion?

Answer :

The concentration of hydroxide ions in the solution is 0.0428 M.

Ions are what?

A molecule or atom that has a net electrical charge is called an ion.

The balanced equation for the reaction between HCl and Ca(OH)2 is:

Ca(OH)2 + 2HCl -> CaCl2 + 2H2O

The number of moles of HCl added at the equivalence point can be found by multiplying the volume of HCl added (in liters) by its concentration in moles/liter:

moles HCl = (38.1 mL HCl x 0.028 mol/L HCl) / 1000 mL/L = 0.00107 mol HCl

The concentration of hydroxide ions can be found by dividing the number of moles of hydroxide ions by the volume of the solution:

[OH-] = moles OH- / L of solution

We know that the number of moles of HCl added is equal to the number of moles of OH- present, so:

[OH-] = 0.00107 mol OH- / (25.0 mL / 1000 mL/L) = 0.0428 M

Therefore, the concentration of hydroxide ions in the solution is 0.0428 M.

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