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Answer :
The number of moles of NaCl present in 276.50 mL of 1.55 M NaCl solution is 0.429 mol.
To find the number of moles of NaCl in a given solution, we can use the formula: moles of solute = concentration of solution x volume of solution We are given the following information:Concentration of solution = 1.55 MVolume of solution = 276.50 mL
To use this formula, we need to convert the volume of the solution from milliliters (mL) to liters (L).1 L = 1000 mLTherefore, 276.50 mL = 0.27650 LNow, we can substitute the given values in the formula and calculate the number of moles of NaCl present in the solution:moles of solute = concentration of solution x volume of solution= 1.55 M x 0.27650 L= 0.429 molTherefore, there are 0.429 moles of NaCl in 276.50 mL of 1.55 M NaCl solution. Hence, the correct option is 0.429.
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