High School

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Select the equation that most accurately depicts the word problem.

The perimeter of a rectangle is 68 inches. The perimeter equals twice the length of [tex]L[/tex] inches, plus twice the width of 9 inches.

A. [tex]68 = 2(L - 9)[/tex]

B. [tex]68 = 9L + 2[/tex]

C. [tex]68 = 2L + 2/9[/tex]

D. [tex]68 = 2L + 2(9)[/tex]

E. [tex]68 = 9(L + 2)[/tex]

F. [tex]68 = \pm 2 + 2(9)[/tex]

Answer :

To solve this problem, we need to understand how to calculate the perimeter of a rectangle. The formula for the perimeter [tex]\( P \)[/tex] of a rectangle is given by:

[tex]\[ P = 2L + 2W \][/tex]

where [tex]\( L \)[/tex] is the length and [tex]\( W \)[/tex] is the width of the rectangle.

Now, let's go step-by-step through the details provided in the problem:

1. Perimeter of the Rectangle: The perimeter is given as 68 inches.

2. Width of the Rectangle: The width [tex]\( W \)[/tex] is provided as 9 inches.

Using the formula for the perimeter, we can substitute what we know:

[tex]\[ 68 = 2L + 2 \times 9 \][/tex]

Let's simplify this equation:

- Calculate [tex]\( 2 \times 9 \)[/tex]: This equals 18.

Therefore, the equation simplifies to:

[tex]\[ 68 = 2L + 18 \][/tex]

From the multiple-choice options given in the problem, the correct equation is:

[tex]\[ 68 = 2L + 2(9) \][/tex]

This choice accurately represents how the perimeter of the rectangle is calculated using the given length and width values.

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