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public class test {
public static void main(String[] args) {
int n = 10000 * 10000 * 10000;
System.out.println("n is " + n);
}
}

Choose the correct statement:

A. The program displays "n is 1000000000000".

B. The result of 10000 * 10000 * 10000 is too large to be stored in an int variable n. This causes an overflow and the program is aborted.

C. The result of 10000 * 10000 * 10000 is too large to be stored in an int variable n. This causes an overflow and the program continues to execute because Java does not report errors on overflow.

D. The result of 10000 * 10000 * 10000 is too large to be stored in an int variable n. This causes an underflow and the program is aborted.

E. The result of 10000 * 10000 * 10000 is too large to be stored in an int variable n. This causes an underflow and the program continues to execute because Java does not report errors on underflow.

Answer :

Final answer:

The Java program in the class test tries to store a value too large for an int data type, leading to an overflow. Yet, the program does not abort but continues executing due to Java's handling of overflows. It's advisable to use a larger data type for such large values.

Explanation:

In the given class test, the result of 10000 * 10000 * 10000 is indeed too large to be stored in an int variable n. This operation results in a number that exceeds the maximum limit of an integer in Java, which leads to a situation known as overflow. However, Java does not abort the program or report any errors when overflow occurs. Instead, the program continues to execute, resulting in an incorrect output due to integer overflow. To solve this, you would need to use a data type that can handle larger numbers, such as a long or BigInteger.

Learn more about Overflow in Java here:

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