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Answer :
The pressure on a 92 kg person 99 m deep in freshwater is 1071615 Pascals or approximately 10.58 atmospheres, calculated using the formula P =
gh + P_{atm}, density of freshwater, gravity, and depth.
The pressure on a 92 kg person at 99 m deep in freshwater is calculated using the equation P =
gh + P_{atm}, where is the density of the liquid, g is the acceleration due to gravity, and h is the depth. The atmospheric pressure (P_{atm}) at sea level is approximately 101325 Pascals (Pa). The density of freshwater (
) is 1000 kg/m³, and the standard gravity (g) is 9.81 m/s².
The pressure due to the liquid at 99 m depth without including atmospheric pressure is:
P_{liquid} =
imes g imes h = 1000 kg/m³ imes 9.81 m/s² imes 99 m = 970290 Pa,
The total pressure including the atmospheric pressure is:
P_{total} = P_{liquid} + P_{atm} = 970290 Pa + 101325 Pa = 1071615 Pa.
To express the pressure in atmospheres:
1 atm = 101325 Pa, therefore:
P_{total} (atm) = 1071615 Pa / 101325 Pa/atm ≈ 10.58 atm.
The pressure at 99 m depth in freshwater on a 92 kg person is 1071615 Pascals or approximately 10.58 atmospheres.
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