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Answer :
d.-117 is the value of ∫¹⁸₂ (f(x)−8)dx.
The value of ∫¹⁸₂ (f(x)−8)dx can be determined by subtracting 8 times the integral of f(x) from 2 to 18 from 2 to 18 of f(x).
Given that ∫¹⁸₂ f(x)dx = 11, we can calculate:
∫¹⁸₂ (f(x)−8)dx = ∫¹⁸₂ f(x)dx - 8*(18-2) = 11 - 8*16 = 11 - 128 = -117.
Therefore, the value of ∫¹⁸₂ (f(x)−8)dx is -117.
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