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Answer :
Final answer:
The limit as x approaches 0 for the function 2x+162 is 162. The notation lim->(x,0)=4 seems to be a typo or an error, as the correct result is 162, not 4.
Explanation:
The question is about the limit of a function as x approaches 0. In this case, the function is given as 2x+162. When we substitute x=0 into the function, we get 2(0)+162 = 162. Since the limit as x approaches 0 of the function 2x+162 is the same value as when we substitute x=0 into the function, we can say that the limit as x approaches 0 for the function 2x+162 is 162.
The notation lim->(x,0)=4 seems out of place and not related to the function 2x+162, as when x=0 in the function 2x+162, the answer is 162, not 4. This seems to be a typo or an error in the question.
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