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Answer :
Final answer:
The density of the gold nugget, calculated by dividing its mass (321g) by the volume it displaces in the water (21.1 cm³), is approximately 15.2 g/cm³.
Explanation:
The density of the gold can be calculated from the measurements given using the formula for density, which is mass divided by volume (Density = Mass/Volume).
In this case, we need to first find the volume the gold nugget occupies, which we can determine from the change in water level. The volume of the nugget is the final volume minus the initial volume of the water.
36.6 mL - 15.5 mL = 21.1 mL.
We now know the volume of the gold nugget is 21.1 mL, where 1 mL is equivalent to 1 cm³. Therefore, the volume is 21.1 cm³.
The mass of the nugget is given as 321 g. Substituting these values into the formula gives us:
Density = 321 g / 21.1 cm³ = 15.2 g/cm³.
This value is close to the known density of gold, which is about 19.3 g/cm³.
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