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Answer :
Final answer:
The period of a simple pendulum with a length of 1.65 m and undergoing simple harmonic motion in a gravity field of 9.8 m/s² is approximately 2.5768 seconds.
Explanation:
To determine the period of a simple pendulum undergoing simple harmonic motion, we use the formula for the period (T) of a pendulum:
T = 2π√(L/g)
Where:
- L is the length of the pendulum (in meters)
- g is the acceleration due to gravity (in meters per second squared)
In this case, L is 1.65 m and g is 9.8 m/s2. Inserting these values into the equation provides us with the period:
T = 2π√(1.65/9.8)
Calculating the square root and the multiplication by 2π gives us the period of the pendulum in seconds:
T = 2π√(0.16836735...) ≈ 2π(0.410325...) ≈ 2.5768 s
Therefore, the period of the pendulum is approximately 2.5768 seconds.
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