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What is the pressure of helium inside a container that holds 2.4 atm of radon, 1.37 atm of neon, and has a total pressure of 5.0 atm?

Answer :

The pressure of helium in the container is 1.23 atm, calculated by subtracting the sum of the other gases' partial pressures from the total pressure inside the container.

The pressure of helium inside the container can be calculated using Dalton's Law of Partial Pressures, which states that the total pressure of a gas mixture is the sum of the partial pressures of each individual gas. Given that the total pressure is 5.0 atm and the pressures of the other gases are 2.4 atm for radon and 1.37 atm for neon, the pressure of helium can be found by subtracting the sum of the known partial pressures from the total pressure.

Total pressure (Ptotal) = 5.0 atm
Pressure of radon (Pradon) = 2.4 atm
Pressure of neon (Pneon) = 1.37 atm
Pressure of helium (Phelium) = Ptotal - (Pradon + Pneon)

Therefore, the pressure of helium (Phelium) is:

Phelium = 5.0 atm - (2.4 atm + 1.37 atm)
Phelium = 5.0 atm - 3.77 atm
Phelium = 1.23 atm

The pressure of helium is 1.23 atmospheric (atm).

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