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Answer :
Final answer:
To find the cost of each flag, we can set up a system of equations. Solving this system of equations, we find that each small flag costs 18 AED and each large flag costs 36 AED.
Explanation:
To find the cost of each flag, we need to set up a system of equations based on the given information. Let's assume the cost of each small flag is 'x' AED and the cost of each large flag is 'y' AED.
From the first order, we have:
- 12 small flags * 'x' AED + 6 large flags * 'y' AED = 432 AED
From the second order, we have:
- 9 small flags * 'x' AED + 3 large flags * 'y' AED = 270 AED
We can now solve this system of equations using substitution or elimination. Let's use the elimination method.
- 2 * (9 small flags * 'x' AED + 3 large flags * 'y' AED) = 2 * 270 AED
- 12 small flags * 'x' AED + 6 large flags * 'y' AED = 432 AED
- This simplifies to:
- 18 small flags * 'x' AED + 6 large flags * 'y' AED = 540 AED
- 12 small flags * 'x' AED + 6 large flags * 'y' AED = 432 AED
Subtracting the second equation from the first equation gives:
- (18 small flags - 12 small flags) * 'x' AED + (6 large flags - 6 large flags) * 'y' AED = 540 AED - 432 AED
- 6 small flags * 'x' AED = 108 AED
- 'x' AED = 108 AED / 6 small flags
- 'x' AED = 18 AED
So, each small flag costs 18 AED. Now, we can substitute this value of 'x' into any of the original equations to find the cost of each large flag. Let's use the first equation:
- 12 * 18 AED + 6 large flags * 'y' AED = 432 AED
- 216 AED + 6 large flags * 'y' AED = 432 AED
- 6 large flags * 'y' AED = 432 AED - 216 AED
- 6 large flags * 'y' AED = 216 AED
- 'y' AED = 216 AED / 6 large flags
- 'y' AED = 36 AED
So, each large flag costs 36 AED.
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Rewritten by : Barada
A small flag costs 18 AED and a large flag costs 36 AED.
Let us denote the price of a small flag as "s" and the price of a large flag as "l". Based on the information provided, we can then construct two equations:
1st Equation: [tex]12s + 6l = 432[/tex]
2nd Equation: [tex]9s + 3l = 270[/tex]
Equation 1 can be simplified by dividing both sides by 6:
[tex]2s + l = 72[/tex]
Equation 2 can also be simplified by dividing both sides by 3:
[tex]3s + l = 90[/tex]
We now have two equations with two variables that can be solved by elimination or substitution. Let us employ elimination:
[tex](3s + l) - (2s + l) = 90 - 72\ss = 18[/tex]
Now we can solve for l by substituting this value for s into either Equation 1 or Equation 2. Let's look at Equation 1:
[tex]2(18) + l = 72\sl = 36[/tex]
As a result, a small flag costs 18 AED, while a large flag costs 36 AED.
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