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Two resistors, 7 ohms and 6 ohms, are connected in parallel with a 7 V battery. What is the current \( I \) through the battery in amperes?

Answer :

When two resistors, 7 ohms and 6 ohms, are connected in parallel with a 7 V battery, the current is found to be approximately 1.55 A.

To find the total resistance of the parallel combination of the two resistors, we use the formula:

1/R(total) = 1/R1 + 1/R2

Substituting the given values:

1/R(total) = 1/7 + 1/6

Simplifying the equation:

1/R(total) = (6 + 7)/(7 * 6)

1/R(total) = 13/42

R(total) = 42/13

Now, we can use Ohm's Law to calculate the current (I) through the battery:

I = V/R(total)

Substituting the given voltage (V = 7 V) and the calculated resistance (R(total) = 42/13):

I = 7 / (42/13)

I ≈ 1.55 A

Therefore, the current flowing through the battery is approximately 1.55 amperes (A).

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