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Answer :
Final answer:
To find the number of lithium (Li) atoms in 97.9 g of Li, divide the mass by the molar mass of Li, and multiply by Avogadro's number. We get 8.49 x 10^24 atoms.
Explanation:
To determine the number of lithium (Li) atoms in 97.9 g of Li, we need to use the concept of moles and Avogadro's number. The molar mass of Li is 6.94 g/mol, which means that one mole of Li is equal to 6.02 x 10^23 atoms.
To find the number of moles in 97.9 g of Li, we divide the mass by the molar mass:
97.9 g / 6.94 g/mol = 14.11 mol
Finally, to find the number of atoms, we multiply the number of moles by Avogadro's number:
14.11 mol x 6.02 x 10^23 atoms/mol = 8.49 x 10^24 atoms
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