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Answer :
To administer 7 meq of potassium chloride from a vial containing 20 meq in 10 mL, a veterinarian would add 3.5 mL of the solution to the IV fluids.
The question involves the calculation of the volume of potassium chloride (KCl) to be added to an IV solution based on a given concentration and dose ordered by a veterinarian. In this case, the veterinarian has ordered 7 meq of potassium chloride, and the available vial contains 20 meq in 10 mL. To determine the amount to be administered, we use a simple ratio and proportion calculation.
First, we set up the ratio such that:
20 meq : 10 mL = 7 meq : x mL
Next, we solve for x:
20 meq × x mL = 7 meq × 10 mL
x = (7 meq × 10 mL) / 20 meq
x = 70 meq×mL / 20 meq
x = 3.5 mL
Therefore, 3.5 mL of the potassium chloride solution will be added to the IV fluids.
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If the vial is labeled as 20 meq in 10 ml and the veterinarian orders 7 meq of potassium chloride, then 3.5 milliliters of potassium chloride will be added to the IV fluids.
To determine how many milliliters of potassium chloride will be added to the IV fluids, we can use a proportion based on the concentration of the vial.
The vial is labeled as 20 meq in 10 ml. This means that in 10 ml of solution, there are 20 milliequivalents of potassium chloride.
We know that the veterinarian ordered 7 meq of potassium chloride to be added to the IV fluids.
So, we can set up the following proportion:
20 meq / 10 ml = 7 meq / x ml
To solve for x, we can cross-multiply and divide:
20 meq * x ml = 7 meq * 10 ml
20x = 70
x = 70 / 20
x = 3.5 ml
Therefore, 3.5 milliliters of potassium chloride will need to be added to the IV fluids.
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