High School

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The vapor pressure of ethanol is 114.9 mm Hg at 37.1 °C. Its molar heat of vaporization is 39.3 kJ/mol. What is the vapor pressure of ethanol, in mm Hg, at 22.4 °C?

Answer :

Final answer:

The student's question requires the use of the Clausius-Clapeyron equation to find the vapor pressure of ethanol at a new temperature, but the necessary complete calculation process is not provided.

Explanation:

The student's question relates to the calculation of the vapor pressure of ethanol at a different temperature using the Clausius-Clapeyron equation, which is a way to quantify the relationship between the vapor pressure and temperature of a substance given its molar heat of vaporization. To calculate the new vapor pressure at 22.4 °C, we would first need to convert the given temperatures and vapor pressures into Kelvin and Pascals, respectively, then apply the Clausius-Clapeyron equation to derive the constant and solve for the vapor pressure at the new temperature. Unfortunately, this process has not been completed in the question, and instead, additional data is provided in the form of vapor pressures at different temperatures, suggesting the use of the same equation to estimate the enthalpy of vaporization. Without the actual calculation process for solving the student's original question, it is impossible to give a precise answer here.

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