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What is the amount of work done by the applied force when a 10 kg object is lifted 2 meters at constant speed?

Note: The standard acceleration due to gravity is [tex]9.80665 \, \text{m/s}^2[/tex].

A. 98 joules
B. 196 joules
C. 196 newton meters
D. 153 newton meters
E. 27 joules

Answer :

The amount of work done by the applied force is 196.133 Joules.

When a 10 kg object is lifted 2 meters at a constant speed, the amount of work done by the applied force can be calculated using the formula: Work = Force × Distance. The force required to lift the object can be determined using the equation: Force = Mass × Acceleration. In this case, the acceleration is equal to the standard acceleration of gravity, which is approximately 9.80665 m/s².

Using the formula for force, we find that the force required to lift the object is: Force = 10 kg × 9.80665 m/s² = 98.0665 Newtons.

Now, we can calculate the work done by the applied force: Work = Force × Distance = 98.0665 N × 2 m = 196.133 Newton meters or Joules.

Therefore, the amount of work done by the applied force when a 10 kg object is lifted 2 meters at constant speed is 196.133 Joules.

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