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Given:
- [tex]jk \parallel lm[/tex]
- [tex]jk = lm[/tex]
- [tex]l[/tex] is the midpoint of [tex]jn[/tex]

Prove: [tex]\triangle jlk \cong \triangle lnm[/tex]

Statements:
1. [tex]jk \parallel lm[/tex]
2. [tex]jk = lm[/tex]
3. [tex]l[/tex] is the midpoint of [tex]jn[/tex]
4. [tex]jl = ln[/tex]
5. [tex]\angle jlk \cong \angle lnm[/tex]
6. [tex]\triangle jlk \cong \triangle lnm[/tex]

Reasons:
1. Given
2. Given
3. Given
4. Definition of midpoint
5. Corresponding Angles Theorem
6. SAS (Side-Angle-Side) Congruence Theorem

Answer :

We have proven that ∠AJLK is congruent to ∠ALNM based on the SAS congruence criteria, the definition of midpoint, and the corresponding angles theorem.

To prove that ∠AJLK = ∠ALNM, we can use the SAS (Side-Angle-Side) congruence criteria along with the definitions of midpoint and corresponding angles theorem.

JK || LM. (Given)

JK = LM. (Given)

L is the midpoint of JN. (Given)

JL = LN. (Definition of midpoint)

By using the SAS congruence criteria, we can establish the congruence of triangles JKL and LNM.

Triangle JKL ≅ Triangle LNM. (SAS congruence)

According to the corresponding angles theorem, corresponding angles of congruent triangles are congruent.

∠AJK = ∠ALM. (Corresponding angles of congruent triangles)

Since L is the midpoint of JN, we can infer the following:

∠AJL = ∠ALN. (Definition of midpoint)

Combining statements 6 and 7, we can conclude:

∠AJLK = ∠ALNM. (Angle addition)

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