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Three point charges of -2.00 µC, 4.00 µC, and 2.00 µC are placed along the x-axis as shown in the figure. What is the change in the electric potential energy of the system if a -2.00 µC is brought in from far away and placed at point P?

Answer :

Final answer:

The change in electric potential energy of the system can be calculated by considering the work done to bring the -2.00 µC charge from far away to point P. The electric potential energy is given by the formula: ΔU = qV, where ΔU is the change in potential energy, q is the charge, and V is the electric potential.

Explanation:

The change in electric potential energy of the system can be calculated by considering the work done to bring the -2.00 µC charge from far away to point P. The electric potential energy is given by the formula:

ΔU = qV

where ΔU is the change in potential energy, q is the charge, and V is the electric potential. Since only one charge is brought from far away, we only need to calculate the electric potential at point P due to the other three charges. We can use the formula:

V = kQ/r

where k is the constant, Q is the charge creating the potential, and r is the distance from the charge to the point P.

Using these formulas and the given charges and distances, we can calculate the change in electric potential energy of the system when the -2.00 µC charge is brought in from far away and placed at point P.

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