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A black mamba snake has a length of 2.60 m and a top speed of 4.60 m/s. Suppose a mongoose and a black mamba find themselves nose to nose. In an effort to escape, the snake accelerates past the mongoose at 8.75 m/s² from rest.

How much time does the mongoose have to react before the black mamba's tail passes the mongoose's nose?

Answer :

Final Answer:

The mongoose has approximately 0.525 seconds to react before the black mamba's tail passes its nose.

Explanation:

To determine the time the mongoose has to react, we can use the following equations of motion:

1. The distance covered by the black mamba as it accelerates from rest can be calculated using the equation:

[tex]\[s = ut + \frac{1}{2}at^2\][/tex]

where:

s = distance covered (which is the length of the snake, 2.60 m)

u = initial velocity (0 m/s, as the snake starts from rest)

a = acceleration (8.75 m/s²)

t = time

2. We want to find the time it takes for the snake to accelerate to its top speed, so we can use the equation:

[tex]\[v = u + at\][/tex]

where:

v = final velocity (4.60 m/s, the snake's top speed)

u = initial velocity (0 m/s)

a = acceleration (8.75 m/s²)

t = time

Rearranging the second equation to solve for time, we get:

[tex]\[t = \frac{v}{a}\][/tex]

Substituting the values, we find:

[tex]\[t = \frac{4.60\, m/s}{8.75\, m/s^2} \approx 0.525\, s\][/tex]

So, the snake takes approximately 0.525 seconds to accelerate to its top speed. During this time, the mongoose must react. Since the snake has a head start, the mongoose has approximately 0.525 seconds to react before the snake's tail passes its nose.

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