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A 7000 kg helicopter accelerates upward at [tex]3 \, \text{m/s}^2[/tex]. What lift force is exerted by the air on the helicopter's propellers?

A. 7000 N
B. 14000 N
C. 21000 N
D. 28000 N

Answer :

Final answer:

The lift force exerted by the air on the helicopter's propellers is 89600 N.

Explanation:

When a helicopter accelerates upwards, the lift force exerted by the air on the helicopter's propellers is equal to the weight of the helicopter plus the force required to accelerate it. The weight of the helicopter is given by the product of its mass and the acceleration due to gravity, which is approximately 9.8 m/s² on Earth. In this case, the lift force can be calculated as follows:

Lift force = Weight of the helicopter + Force required to accelerate it

= (mass of the helicopter × acceleration due to gravity) + (mass of the helicopter × acceleration)

= (7000 kg × 9.8 m/s²) + (7000 kg × 3 m/s²)

= 68600 N + 21000 N

= 89600 N

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