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Answer :
Answer:
0.424 J/g °C
General Formulas and Concepts:
Math
Pre-Algebra
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
- Left to Right
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality
Chemistry
Thermochemistry
Specific Heat Formula: q = mcΔT
- q is heat (in Joules)
- m is mass (in grams)
- c is specific heat (in J/g °C)
- ΔT is change in temperature
Explanation:
Step 1: Define
[Given] m = 38.8 g
[Given] q = 181 J
[Given] ΔT = 36.0 °C - 25.0 °C = 11.0 °C
[Solve] c
Step 2: Solve for Specific Heat
- Substitute in variables [Specific Heat Formula]: 181 J = (38.8 g)c(11.0 °C)
- Multiply: 181 J = (426.8 g °C)c
- [Division Property of Equality] Isolate c: 0.424086 J/g °C = c
- Rewrite: c = 0.424086 J/g °C
Step 3: Check
Follow sig fig rules and round. We are given 3 sig figs.
0.424086 J/g °C ≈ 0.424 J/g °C
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