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Answer :
Let's solve the given problem step-by-step:
Part (a): Finding the Formula
The woman starts with a weight of 107 pounds. She hopes her weight multiplies by 1.06 each week. This describes an exponential growth model.
The general formula for an exponential function can be written as:
[tex]w(t) = w_0 \cdot r^t[/tex]
Where:
- [tex]w(t)[/tex] is the weight after [tex]t[/tex] weeks.
- [tex]w_0[/tex] is the initial weight.
- [tex]r[/tex] is the growth rate.
For this problem, [tex]w_0 = 107[/tex] (her current weight), and [tex]r = 1.06[/tex] (the growth factor per week). Therefore, the exponential function is:
[tex]w(t) = 107 \cdot 1.06^t[/tex]
This formula gives us the woman's weight [tex]w[/tex] in pounds after [tex]t[/tex] weeks.
Part (b): Finding How Long It Will Take to Reach 125 Pounds
We need to find the time [tex]t[/tex] when her weight reaches 125 pounds, which means solving the equation:
[tex]125 = 107 \cdot 1.06^t[/tex]
Divide both sides by 107 to isolate the exponential expression:
[tex]\frac{125}{107} = 1.06^t[/tex]
Calculating the left side gives approximately:
[tex]1.1682 \approx 1.06^t[/tex]
To solve for [tex]t[/tex], take the logarithm of both sides. Using the natural logarithm [tex]\ln[/tex]:
[tex]\ln(1.1682) = \ln(1.06^t)[/tex]
Using the power rule for logarithms, [tex]\ln(a^b) = b \cdot \ln(a)[/tex], this becomes:
[tex]\ln(1.1682) = t \cdot \ln(1.06)[/tex]
Solve for [tex]t[/tex]:
[tex]t = \frac{\ln(1.1682)}{\ln(1.06)}[/tex]
Calculating this gives:
[tex]t \approx \frac{0.1552}{0.0583} \approx 2.66[/tex]
Therefore, it will take approximately 2.66 weeks for the woman to reach her normal weight of 125 pounds.
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