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What is the volume of a cylinder with a height of 18.6 inches and a base with a radius of 6.2 inches, to the nearest tenth of a cubic inch?

Answer :

To find the volume of a cylinder, we use the formula

[tex]$$
V = \pi r^2 h,
$$[/tex]

where [tex]$r$[/tex] is the radius of the base and [tex]$h$[/tex] is the height of the cylinder.

1. First, we square the radius. With [tex]$r = 6.2$[/tex] in, we have

[tex]$$
r^2 = (6.2)^2 = 38.44.
$$[/tex]

2. Next, multiply by [tex]$\pi$[/tex] to calculate the area of the circular base:

[tex]$$
\text{Area} = \pi \times 38.44.
$$[/tex]

3. Multiply the base area by the height [tex]$h = 18.6$[/tex] in to obtain the volume:

[tex]$$
V = \pi \times 38.44 \times 18.6.
$$[/tex]

4. Completing the multiplication, we find that

[tex]$$
V \approx 2246.188481834245 \text{ cubic inches}.
$$[/tex]

5. Finally, rounding this result to the nearest tenth gives

[tex]$$
V \approx 2246.2 \text{ cubic inches}.
$$[/tex]

Thus, the volume of the cylinder is approximately [tex]$2246.2$[/tex] cubic inches.

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