High School

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A car’s value depreciates at a rate of 3.4% per year. The car was worth $30,000 when it was new.

Which equation could be used to determine when the car will be worth $18,500, where \(x\) is time in years?

A. \(18500 = 30000 \times (0.034)^x\)

B. \(18500 = 30000 \times (0.966)^x\)

C. \(30000 = 18500 \times (0.34)^x\)

D. \(30000 = 18500 \times (0.966)^x\)

Answer :

It should be D.30000 = 18500

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