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Answer :
Final answer:
With 214.5 kJ of heat energy, 255.76 grams of ethanol can be boiled. We divide the total heat energy by the molar heat of vaporization, then multiply it by the molar mass and hence the correct answer is 214.5 kJ.
Explanation:
The question asks how many grams of ethanol, C₂H₅OH, can be boiled with 214.5 kJ of heat energy, given that the molar heat of vaporization of ethanol is 38.6 kJ/mol. To find the number of moles of ethanol that can be vaporized, we divide the total heat energy by the molar heat of vaporization: 214.5 kJ ÷ 38.6 kJ/mol = 5.56 moles.
Knowing the molar mass of ethanol is 46 g/mol, the mass of ethanol that can be vaporized can be calculated by multiplying the number of moles by the molar mass: 5.56 moles × 46 g/mol = 255.76 grams. Therefore, 255.76 grams of ethanol can be boiled with 214.5 kJ of heat energy.
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