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Which inequality models this problem?

The length of a rectangle is three times its width. If the perimeter is at most 112 centimeters, what is the greatest possible value for the width?

A. [tex]2w + 2 \cdot (3w) > 112[/tex]
B. [tex]2w + 2 \cdot (3w) \leq 112[/tex]
C. [tex]2w + 2 \cdot (3w) \geq 112[/tex]
D. [tex]2w + 2 \cdot (3w) < 112[/tex]

Answer :

The inequality that models this problem is 2(3w) * 2w ≤112

Let the length of the rectangle be "l"

Let the width of the rectangle be "w"

The formula for calculating the perimeter of a rectangle is expressed as:

P = 2(l+w)

If the length of a rectangle is three times its width, this is expressed as:

l = 3w

If the perimeter is at most 112cm, hence;

P ≤112

2(l+w) ≤112

2(3w+w) ≤112

2(3w) * 2w ≤112

Hence the inequality that models this problem is 2(3w) * 2w ≤112

Learn more on inequalities here: https://brainly.com/question/15816805

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