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Answer :
Final answer:
To find the consecutive numbers with a difference of 141, set up the equation (x+1)^2 - x^2 = 141 and solve for x. The first number is 70 and the second number is 71.
Explanation:
To find the consecutive numbers with a difference of 141, we can set up the equation (x+1)^2 - x^2 = 141, where x represents the first number.
Simplifying the equation, we have x^2 + 2x + 1 - x^2 = 141.
Combining like terms, we get 2x + 1 = 141.
Subtracting 1 from both sides, we have 2x = 140.
Dividing both sides by 2, we find x = 70.
So the two consecutive numbers are 70 and 71.
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