High School

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A constant force \( F \) was applied to an object for a time interval of 0.02 s. If the magnitude of the impulse delivered by this force is equal to 8 N·s, what was the magnitude of \( F \)?

A. 0.16 N
B. 400 N
C. 160 N
D. 25 N
E. 250 N

Answer :

Final answer:

The magnitude of the force applied to the object, given an impulse of 8 N:s and a time interval of 0.02 seconds, is 400 N. This is calculated using the formula: Force = Impulse / Time.

Explanation:

The question involves understanding the relationship between force, impulse, and time. Impulse is defined as the product of the force applied to an object and the time interval over which it is applied. It is mathematically represented as Impulse = Force × Time. The given impulse value in this question is 8 N:s (Newton seconds), and the time interval is 0.02 s. To find the force, you need to rearrange the formula to: Force = Impulse / Time.

Substituting the given values, we find that: Force = 8 N:s / 0.02 s = 400 N.

Therefore, the magnitude of the force applied to the object was 400 N.

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