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Answer :
3H2+N2→2NH3
here h2 H2 is limiting reagent
6moles of H2 will give 4moles of NH3
V of NH3 produced=22.4*4L
here h2 H2 is limiting reagent
6moles of H2 will give 4moles of NH3
V of NH3 produced=22.4*4L
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Answer:
89.6 liters
Explanation:
H2 is the limiting reagens
1:3
=> 6 mol N2 + 6 mol H2
=> 5 mol N2 + 3 mol H2
=> 4 mol N2 + 0 mol H2 ( U should go on until all of your limiting reagens are used)
=> 4 mol NH3
P.V= n.R.T => STP
V= (4mol. 0,082058. 273 K)/ 1 atm
V= 89,6 liters
