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Answer :
Sure! Let's solve the compound inequality step-by-step:
We have two separate inequalities to solve:
1. [tex]\( 6 - x > 15 \)[/tex]
2. [tex]\( 2x - 9 \geq 3 \)[/tex]
### Solving the first inequality: [tex]\( 6 - x > 15 \)[/tex]
1. Subtract 6 from both sides:
[tex]\[
-x > 15 - 6
\][/tex]
[tex]\[
-x > 9
\][/tex]
2. Multiply by -1 and reverse the inequality sign:
[tex]\[
x < -9
\][/tex]
### Solving the second inequality: [tex]\( 2x - 9 \geq 3 \)[/tex]
1. Add 9 to both sides:
[tex]\[
2x \geq 3 + 9
\][/tex]
[tex]\[
2x \geq 12
\][/tex]
2. Divide by 2:
[tex]\[
x \geq 6
\][/tex]
### Combine the solutions:
The compound inequality uses "or," which means we combine the solutions from both inequalities:
- From [tex]\( 6 - x > 15 \)[/tex], we have [tex]\( x < -9 \)[/tex].
- From [tex]\( 2x - 9 \geq 3 \)[/tex], we have [tex]\( x \geq 6 \)[/tex].
Thus, the solution is [tex]\( x < -9 \)[/tex] or [tex]\( x \geq 6 \)[/tex].
### Choose the correct option:
The correct answer is option D [tex]\( x < -9 \)[/tex] or [tex]\( x \geq 6 \)[/tex].
We have two separate inequalities to solve:
1. [tex]\( 6 - x > 15 \)[/tex]
2. [tex]\( 2x - 9 \geq 3 \)[/tex]
### Solving the first inequality: [tex]\( 6 - x > 15 \)[/tex]
1. Subtract 6 from both sides:
[tex]\[
-x > 15 - 6
\][/tex]
[tex]\[
-x > 9
\][/tex]
2. Multiply by -1 and reverse the inequality sign:
[tex]\[
x < -9
\][/tex]
### Solving the second inequality: [tex]\( 2x - 9 \geq 3 \)[/tex]
1. Add 9 to both sides:
[tex]\[
2x \geq 3 + 9
\][/tex]
[tex]\[
2x \geq 12
\][/tex]
2. Divide by 2:
[tex]\[
x \geq 6
\][/tex]
### Combine the solutions:
The compound inequality uses "or," which means we combine the solutions from both inequalities:
- From [tex]\( 6 - x > 15 \)[/tex], we have [tex]\( x < -9 \)[/tex].
- From [tex]\( 2x - 9 \geq 3 \)[/tex], we have [tex]\( x \geq 6 \)[/tex].
Thus, the solution is [tex]\( x < -9 \)[/tex] or [tex]\( x \geq 6 \)[/tex].
### Choose the correct option:
The correct answer is option D [tex]\( x < -9 \)[/tex] or [tex]\( x \geq 6 \)[/tex].
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