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Answer :
Final answer:
The launch angle of the rocket from the horizontal can be calculated using the inverse tangent function of the initial vertical velocity divided by the initial horizontal velocity, resulting in an angle of approximately 63.43°.
Explanation:
To find out at what angle from the horizontal a rocket is launched when given its initial horizontal velocity and initial vertical velocity, we can use the tangent function. The tangent of the launch angle is equal to the initial vertical velocity divided by the initial horizontal velocity.
The formula is θ = tan⁻¹(vy / vx).
In this case, the initial horizontal velocity (vx) is 4.8 m/s and the initial vertical velocity (vy) is 9.5 m/s.
Plugging these values into the formula:
θ = tan⁻¹(9.5 m/s / 4.8 m/s)
≈ tan⁻¹(1.979)
≈ 63.43°
Therefore, the rocket is launched at an angle of approximately 63.43° from the horizontal.
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