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You place a 3.0 m long board symmetrically across a 0.5 m wide chair to seat three physics students at a party at your house. If 67 kg Dan sits on the left end of the board and 50 kg Tahreen on the right end of the board, where should 54 kg Komila sit to keep the board stable?

Answer :

To keep the board stable, Komila should sit at a specific position that balances the torques exerted by Dan and Tahreen. The stability of the board depends on the principle of torque equilibrium.

(a) To find the position where Komila should sit, we need to consider the torques exerted by Dan and Tahreen. The torque is calculated by multiplying the force applied by the distance from the pivot point.

(b) Since the board is symmetrically placed across the chair, the pivot point is at the center of the board. To achieve torque equilibrium, the sum of the torques on both sides of the pivot point should be equal.

(c) The torque exerted by Dan is calculated as torque_Dan = (67 kg) * g * (L/2), where L is the length of the board.

(d) The torque exerted by Tahreen is calculated as torque_Tahreen = (50 kg) * g * (L/2), where L is the length of the board.

(e) To maintain stability, the sum of the torques should be zero, so torque_Dan = torque_Tahreen.

(f) Solving the equation, we can determine the position where Komila should sit to balance the torques and keep the board stable.

To learn more about torques click here : brainly.com/question/31323759

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