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Answer :
Option C is the correct answer. The magnitude of the force required is 90 N.
To keep the beam at rest and horizontal, the clockwise and counterclockwise torques acting on the beam must balance each other. Torque is calculated by multiplying the force applied by the distance from the pivot.
Let's denote the force applied at the other end of the beam as F. The torque due to the 120 N object is given by 120 N × 3 m = 360 N·m (counterclockwise torque). The torque due to the force F is F × 4 m (clockwise torque).
For the beam to be in equilibrium, the sum of the torques must be zero:
360 N·m - F × 4 m = 0
Now, let's solve for F:
F × 4 m = 360 N·m
F = 360 N·m / 4 m
F = 90 N
To keep the beam at rest and horizontal, a force of 90 N must be applied at the other end of the beam, 4 m away from the pivot. Therefore, the correct answer is C. 90 N.
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