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Answer :
Final Answer:
The initial voltage of the cell is +1.37 V, indicating a positive potential difference between electrodes.So, the correct option is E) +1.37 V
Explanation:
The correct answer is option E, +1.37 V. This indicates that the initial voltage of the cell is positive and equals 1.37 volts. This signifies that the cell's electrodes have a potential difference of 1.37 volts.
In electrochemistry, the initial voltage of a cell is determined by the standard reduction potentials of the half-reactions involved. By comparing the given options, it's evident that +1.37 V aligns with the standard reduction potential of a particular cell. This potential indicates the tendency of the cell to undergo reduction, implying a positive voltage.
The positive sign signifies that the reduction half-reaction has a greater tendency to occur spontaneously compared to the oxidation half-reaction. This results in a flow of electrons from the anode to the cathode, generating a positive voltage. Therefore, the initial voltage of the cell is +1.37 V.
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