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A track and field athlete is competing in the hammer throw event. The athlete is 181 cm tall, with an arm length of 90 cm, and is using a standard ball and chain for the event, which is 121 cm long. As the athlete begins to spin, their body becomes the center of the motion, with both arms holding on to the ball and chain handle. If the initial linear velocity of the ball and chain is 29 m/s upon its release, how fast (total angular velocity in radians per second) was the athlete spinning it?

Answer :

Total angular velocity is 13.7 rad/s.

Given that an object is moving in a circular motion, we can infer that the system involving the athlete, the ball, and the rope is also moving in a round fashion.

We are informed that the athlete is 181 cm tall, has a 90 cm arm span, and will be using a 121 cm long ball and chain for the competition. With both arms hanging on to the ball and chain handle as the athlete starts to spin, their body becomes the centre of the action. The ball and chain's initial linear velocity is 29 m/s when it is released.

The radius of the path= 90 cm + 121 cm

= 211cm or 2.11 m

Using;
linear velocity = radius * angular velocity

V = rω

ω = V/r

ω = 29m/s/2.11 m

ω = 13.7 rad/s

angular velocity of athlete is 13.7 rad/s

learn more about angular velocity here

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