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Answer :
Answer:
The problem asks for the number of ways to arrange six differently colored flags with certain constraints. No specific solution can be determined with the given details, as the arrangement depends on rules not provided in the question.
Step-by-step explanation:
The question involves arranging six flags in a line such that no two adjacent flags are of the same color. To find the number of ways to arrange one red flag, three white flags, and two blue flags, we need to consider the constraints given and use combinatorial methods to calculate the arrangements.
Since we cannot have any two identical flags adjacent, we could start with the red flag and alternate the colors. We have to place white flags adjacent to red and blue flags, where possible, to make sure no two identical colored flags are next to each other. Given the fact that we have an odd number of white flags (three), a possible sequence could be Red-White-Blue-White-Blue-White.
Without more specific information regarding the rules for arranging these flags (such as if we can start with any color), we cannot provide a specific number of arrangements. The possible answers provided (a) 12, (b) 48, (c) 72, (d) 144 do not account for the detailed rules of arrangement, so we cannot determine the correct answer from the information given in the question alone.
Question
You have 3 identical red flags, 4 blue flags, and 7 yellow flags. Determine how many ways you can arrange all the flags on a pole if a red flag must be first.
a) 84
b) 144
c) 224
d) 504
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