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Answer :
The sample of Argon gas must be cooled to approximately -174.6 °C in order to compress it from 1.5 m³ to 175 mL.
To find the final temperature, we can use the combined gas law equation:
(P1 * V1) / T1 = (P2 * V2) / T2.
Given that P1 = P2 (since the pressure remains constant)
V1 = 1.5 m³
V2 = 175 mL (which needs to be converted to cubic meters)
T1 = 38.4°C (or 311.55 K)
We can solve for T2.
Converting 175 mL to cubic meters, we get
V2 = 0.000175 m³.
Rearranging the equation and solving for T2 gives
T2 ≈ 98.95 K.
Converting this temperature back to Celsius gives -174.6°C.
The sample of Argon gas needs to be cooled to around -174.6°C .
in order to compress it from 1.5 m³ to 175 mL while keeping the pressure constant.
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The sample of Argon gas must be cooled to approximately -174.6 °C in order to compress it from 1.5 m³ to 175 mL.
To find the final temperature, we can use the combined gas law equation:
(P1 * V1) / T1 = (P2 * V2) / T2. Given that P1 = P2 (since the pressure remains constant), V1 = 1.5 m³, V2 = 175 mL (which needs to be converted to cubic meters), and T1 = 38.4°C (or 311.55 K), we can solve for T2. Converting 175 mL to cubic meters, we get V2 = 0.000175 m³. Rearranging the equation and solving for T2 gives T2 ≈ 98.95 K. Converting this temperature back to Celsius gives -174.6°C. The sample of Argon gas needs to be cooled to around -174.6°C .
in order to compress it from 1.5 m³ to 175 mL while keeping the pressure constant.
To know more about temperature, visit:brainly.com/question/7510619
#SPJ11
