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Answer :
Final answer:
The unbalanced force acting on a 4000kg truck decelerating from 22.0 m/s to 8.0 m/s in 3.50 seconds amount to -16,000N, signifying a resisting or braking force. The provided options (a, b, c, d) don't match the calculated answer.
Explanation:
To calculate the unbalanced forces on the truck, we need to invoke Newton's Second Law of Motion, which asserts that Force equals mass times acceleration (F=ma). The acceleration can be found by dividing the change in velocity by the time it takes for that change to occur. In this case, velocity changes by -14.0 metres per second (from 22.0 to 8.0 m/s) over a duration of 3.50 seconds, so the acceleration is -14.0 m/s / 3.50 s = -4.00 m/s² (note that the negative sign simply indicates a decrease in speed).
Thus, the unbalanced force on the truck is F = ma = (4000 kg)(-4.00 m/s²), resulting in a force of -16,000 Newtons (N). The negative sign merely suggests that the force is acting opposite to the direction of motion, meaning it is a decelerating (or braking) force. However, the choices provided seem to be incorrect according to the calculation. Therefore, based on the data given in the question, none of the options (a, b, c, d) is correct.
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