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Answer :
The velocity after the collision is 27.19 m/s
What is the law of conservation of momentum?
For a collision between Object 1 and Object 2 in an isolated system, the total momentum of the two objects before collision equals the total momentum of the two objects after collision. That is, the momentum lost from object 1 is equal to the momentum gained from object 2 (a constant or unchanging value). It can be stated by following equation:
Pₙ = mₙvₙ
mₙvₙ = m₁v₁ + m₂v₂
Where, Pₙ = final momentum
mₙ = total mass of the system
vₙ = final velocity of the system
For the given case,
Since, mₙvₙ = m₁v₁ + m₂v₂
(m₁ + m₂)vₙ = m₁v₁ + m₂v₂
(925 + 145)vₙ = (925 × 29.5) + (145 × 12.5)
1070 vₙ = 27287.5 + 1812.5
1070 vₙ = 29100
vₙ = [tex]\frac{29100}{1070}[/tex]
vₙ = 27.19 m/s
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