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A stone is thrown vertically upward with an initial speed of 19.5 m/s. It will rise to a maximum height of:

A. 4.9 m
B. 9.8 m
C. 19.4 m
D. 38.8 m
E. none of these

Answer :

The stone will rise to a maximum height of 19.4 m. the stone's initial upward velocity will gradually decrease due to gravity until it reaches its maximum height, at which point its vertical velocity becomes zero. The correct answer is option C, 19.4 meters, as calculated using the kinematic equation.

When a stone is thrown vertically upward, it follows a parabolic trajectory. At its highest point, the stone's velocity will be zero before it starts falling back down. The maximum height can be calculated using the formula:

maximum height = (initial velocity^2)/(2 * acceleration due to gravity)

In this case, the initial velocity is 19.5 m/s and the acceleration due to gravity is 9.8 m/s^2 (assuming no air resistance). Plugging in these values into the formula, we get: maximum height = (19.5^2)/(2 * 9.8) = 19.4 m.

Therefore, the correct answer is option C: 19.4 m.

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