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"53.2 g of [tex]KMnO_4[/tex] reacts in an excess of [tex]HCl[/tex]. How many grams of [tex]Cl_2[/tex] are produced?"

A. 71.6 g
B. 106.4 g
C. 53.2 g
D. 35.8 g

Answer :

Final answer:

To calculate the mass of Cl2 produced, you need to calculate the moles of KMnO4, use the stoichiometric ratio to find the moles of Cl2, and then convert it to grams.

Option D is correct

Explanation:

To find the amount of Cl2 produced, we need to determine the balanced equation and use stoichiometry. The balanced equation for the reaction between KMnO4 and HCl is:

2 KMnO4 + 16 HCl → 2 KCl + 2 MnCl2 + 8 H2O + 5 Cl2

From the balanced equation, we can see that 2 moles of KMnO4 react to produce 5 moles of Cl2. So, to find the moles of Cl2 produced, we can use the ratio:

moles of Cl2 = (moles of KMnO4) * (5 moles Cl2 / 2 moles KMnO4)

Now, we can convert the given mass of KMnO4 to moles:

moles of KMnO4 = (mass of KMnO4) / (molar mass of KMnO4)

Finally, we can substitute the moles of KMnO4 into the equation for moles of Cl2 and convert it back to grams:

mass of Cl2 = (moles of Cl2) * (molar mass of Cl2)

So, to calculate the mass of Cl2, you need to perform the following steps:

  1. Calculate the moles of KMnO4 using the given mass and its molar mass.
  2. Use the ratio of moles of Cl2 to moles of KMnO4 to calculate the moles of Cl2 produced.
  3. Convert the moles of Cl2 to grams using its molar mass.

The correct option is d) 35.8 g.

Learn more about stoichiometry here:

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