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The half-life for the transmutation of Radon-222 (222) to Lead-214 (214) is 3.8 days. If there is an initial mass of 100.0 g of Radon-222, how much Radon-222 would remain after 1.9 days? a) 70.7 g b) 90.0 g c) 75.0 g d) 50.0 g e) 99.9 g f) 25.0 g

Answer :

Final answer:

The half-life is the time required for half of a radioactive substance to decay. Given that the half-life of Radon-222 is 3.8 days, half of its initial mass would remain after 1.9 days, which calculates to about 75.0g from an initial mass of 100.0g.

Explanation:

This question involves understanding the concept of half-life, which is inherent to the field of nuclear physics. The half-life of a radioactive substance is the time required for half of its atoms to decay. Given that the half-life of Radon-222 to Lead-214 is 3.8 days, after one half-life period, half of the original substance would remain, reducing the initial mass of 100.0g to 50.0g.

However, the question asks how much Radon-222 would remain after 1.9 days, which is half of its half-life. Therefore, at this point, ½ of the half-life would have passed, and the substance would have decayed only halfway towards 50.0g. Thus, about 75.0g of Radon-222 would remain (halfway between 100.0g and 50.0g). Therefore, the correct answer is c) 75.0g.

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