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If a bird beats its wings 3000 times in 60 seconds and another bird beats its wings 180 times in 15 seconds, which bird beats its wings faster?

Answer :

To determine which bird beats its wings faster, we need to calculate the rate of beats per second for each bird.

  1. Bird A: Beats its wings 3000 times in 60 seconds.

    • To find the rate in beats per second, divide the total beats by the time in seconds:

    [tex]\text{Rate of Bird A} = \frac{3000 \text{ beats}}{60 \text{ seconds}} = 50 \text{ beats/second}[/tex]

  2. Bird B: Beats its wings 180 times in 15 seconds.

    • Similarly, to find the rate in beats per second, divide the total beats by the time in seconds:

    [tex]\text{Rate of Bird B} = \frac{180 \text{ beats}}{15 \text{ seconds}} = 12 \text{ beats/second}[/tex]

By comparing the two rates:

  • Bird A has a wing beat rate of 50 beats per second.
  • Bird B has a wing beat rate of 12 beats per second.

Therefore, Bird A beats its wings faster than Bird B.

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