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A toy rocket is launched vertically into the air from a launching pad 8 feet above the ground with an initial velocity of 136 feet per second. The height \( h \), in feet, of the rocket above the ground \( t \) seconds after launch is given by the function

\[ h = -16t^2 + 136t + 8 \]

a) How long will it take the rocket to reach its maximum height?

b) What is the maximum height?

Simplify your answer.

Answer :

Step-by-step explanation:

h=-16t^2+136t+8 For this quadratic a = -16 b= 136 c = 8

will reach max height at t = - b/2a = - 136/ (2*-16) = 4.25 s

Plug in 4.25 into the equation for 't' to find max height = 297 ft

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