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Answer :
Answer:
[tex]\text{20 shells}[/tex]
Step-by-step explanation:
[tex]\text{Suppose that Kyra shared }2x\text{ shells, Thomas shared }5x\text{ shells and Zahra}\\\text{shared }3x\text{ shells.}[/tex]
[tex]\text{Thomas and Zahra have 80 shells between them after the shells were divided}\\\text{among the three.}[/tex]
[tex]\therefore\ 5x+3x=80[/tex]
[tex]8x=80[/tex]
[tex]x=10[/tex]
[tex]\text{Number of shells Kyra had = }2x=2(10)=20\text{ shells}[/tex]
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Answer:
Kyra has 20 shells.
Step-by-step explanation:
Kyra, Thomas and Zahra sharing ratio = 2 : 3 : 5
Let x be Kyra's share, since Thomas and Zahra have 80 shells, then Thomas' share
= 3 / (3 + 5) × 80
= 3/8× 80
= 3 ×10
= 30 shells.
Also, total shells shared by the three could be written as: x + 80 and total ratio = 2 + 3 + 5 = 10 therefore same Thomas' share
= 3 / 10 × (x + 80)
= 3(x + 80) / 10
Hence, equate the two values of Thomas' share:
3(x + 80) / 10 = 30
Multiply both sides by 10.
3(x + 80) = 30 × 10
3(x + 80) = 300
Divide both sides by 3
x + 80 = 300 / 3
x + 80 = 100 Add - 80 to both sides.
x = 100 - 80
x = 20.
Therefore, Kyra has 20 shells.